2026/27 Enrolment Open · Free Assessment
TutorVertexMaster Maths. Build Confidence.
CBSE › Class 10 Maths › Areas Related to Circles › Assertion–Reason

CBSE CLASS 10 · CHAPTER 11

Areas Related to Circles Assertion–Reason PYQs Class 10 CBSE (With Answers)

Practise 5 selected Areas Related to Circles Assertion–Reason questions from CBSE Class 10 previous-year board papers and official sample papers. Check each statement, then decide whether the Reason explains the Assertion. Two true statements do not always form a correct explanation.

Showing all 5 questions.

Circumference, sector area and arc length

Key results

  • Circumference = 2πr; area of a circle = πr².
  • Area of a sector = θ360 × πr².
  • Arc length = θ360 × 2πr = πrθ180.
  • Perimeter of a sector = 2r + arc length.
  • Area of a minor segment = area of its sector − area of the corresponding triangle.
  • Here r is the radius and θ is the central angle in degrees.

Question 1 · Basic

Assertion (A): The area of the sector of a circle of radius 14 cm and central angle 90° is 154 cm².

Reason (R): The area of the sector of a circle of radius r and central angle θ is πr² × θ360.

Use π = 227, as instructed in the original paper.

Appeared in: 2023 · Basic · Accessible paper

Answer choices for question 1

Show Answer & Explanation

Official CBSE answer · Explanation by Team TutorVertex

Assertion: True.
Here r = 14 cm and θ = 90°.
Area of sector = θ360 × πr².
= 90360 × 227 × 14 × 14
= 154 cm².

Reason: True.
A sector of angle θ occupies θ360 of the circle.
Its area is θ360 × πr².

Link: R gives the formula used to calculate the area in A, so R explains A. Answer: A.

Question 2 · Standard

Assertion (A): If the circumference of a circle is 176 cm, then its radius is 28 cm.

Reason (R): Circumference = 2π × radius of a circle.

Use π = 227, as instructed in the original paper.

Appeared in: 2024 · Standard

Answer choices for question 2

Show Answer & Explanation

Official CBSE answer · Explanation by Team TutorVertex

Assertion: True.
Let the radius be r cm.
Circumference = 2πr.
176 = 2 × 227 × r.
r = 176 × 744 = 28 cm.

Reason: True.
The circumference of a circle of radius r is 2πr.

Link: R gives the relationship used to find the radius in A, so R explains A. Answer: A.

Question 3 · Standard

Assertion (A): In a circle of radius 21 cm, an arc of length 22 cm subtends an angle of 60° at the centre.

Reason (R): The length of arc of a sector of a circle of radius r and central angle θ is 2πrθ360.

Use π = 227, as instructed in the original paper.

Appeared in: 2026 · Standard · Accessible paper

Answer choices for question 3

Show Answer & Explanation

Official CBSE answer · Explanation by Team TutorVertex

Assertion: True.
Here the arc length is 22 cm and r = 21 cm.
Let the central angle be θ°.
Arc length = θ360 × 2πr.
22 = θ360 × 2 × 227 × 21.
θ = 22 × 360132 = 60°.

Reason: True.
An arc subtending θ degrees occupies θ360 of the full circumference.
Therefore its length is 2πrθ360.

Link: R gives the arc-length formula used to obtain 60°, so R explains A. Answer: A.

Question 4 · Basic

Assertion (A): Area of a sector of a circle with radius r and angle with degree measure θ is θ360 × 2πr.

Reason (R): Area of segment of a circle = Area of the corresponding sector − Area of the corresponding triangle.

Appeared in: 2025 · Basic · Supplementary examination

Answer choices for question 4

Show Answer & Explanation

Official CBSE answer · Explanation by Team TutorVertex

Assertion: False.
The area of a sector is θ360 × πr².
The printed expression θ360 × 2πr gives arc length, not area.

Reason: True for the corresponding minor segment.
Join the centre to the ends of its chord.
The minor sector consists of that segment and the triangle.
Hence area of segment = area of sector − area of triangle.

Link: A uses an arc-length formula for an area. R states the sector-minus-triangle result. A is false and R is true. Answer: D.

Question 5 · Standard

Assertion (A): If the radius of sector of a circle is reduced to its half and angle is doubled then the perimeter of the sector remains the same.

Reason (R): The length of the arc subtending angle θ at the centre of a circle of radius r = πrθ180.

Appeared in: 2024–25 · Standard · Official sample; 2024–25 · Standard · Accessible paper · Official sample

Answer choices for question 5

Show Answer & Explanation

Official CBSE answer · Explanation by Team TutorVertex

Assertion: False.
Let the original radius be r and the original central angle be θ degrees.
Original arc length = πrθ180.
New radius = r2 and new angle = 2θ.
New arc length = π × (r/2) × 2θ180 = πrθ180.
Original perimeter = 2r + πrθ180.
New perimeter = r + πrθ180.
The perimeter decreases by r; it does not remain the same.

Reason: True.
Arc length = θ360 × 2πr = πrθ180.

Link: R correctly gives arc length. Perimeter also includes the two radii, whose total length changes from 2r to r. A is false and R is true. Answer: D.

OriginalChangedrr/2θ2θrr/2
Solution illustration by TutorVertex: the arcs have equal lengths, but the straight sides are shorter. Illustrative angles; not a source diagram.

Common questions

What is the difference between arc length and sector perimeter?

Arc length measures only the curved boundary. Sector perimeter includes that arc and the two radii.

Does halving the radius and doubling the angle preserve sector perimeter?

No. The arc length stays the same, but the two radii together decrease from 2r to r, so the perimeter decreases by r.

How is the area of a minor segment calculated?

Subtract the area of the triangle formed by the two radii and the chord from the area of the corresponding minor sector.

Which value of π should I use?

Use the value specified in the question or in the original paper’s instructions. The numerical board questions here use π = 22/7, as those papers instruct.

How do I find a central angle from an arc length?

Use arc length = (θ/360) × 2πr, substitute the given length and radius, and solve for θ.

Can I use the arc-length formula to calculate sector area?

No. Arc length uses the circumference 2πr; sector area uses the circle’s area πr².

How can units help me check a circle formula?

Area is measured in square units; arc length and perimeter are measured in linear units. For a sector, distinguish (θ/360) × πr² from (θ/360) × 2πr, and include both radii when calculating perimeter.

Official sources and marking schemes

Source labels identify the original paper, set and question number. ZIP links open official archives containing the named paper.

Question source details

Question 1 sources

The A–D choice meanings and order match across the listed papers; capitalisation and punctuation are standardised.

Question 2 sources

The A–D choice meanings and order match across the listed papers; capitalisation and punctuation are standardised.

Question 3 sources

The A–D choice meanings and order match across the listed papers; capitalisation and punctuation are standardised.

Question 4 sources

The A–D choice meanings and order match across the listed papers; capitalisation and punctuation are standardised.

Question 5 sources

Both official sample versions use the same Assertion, Reason and A–D choice order; punctuation and capitalisation are standardised.

Board papers

2023 board papers
2024 board papers
2025 board papers
2026 board papers

Official sample papers

2024–25 sample session

NCERT and syllabus

About these solutions

The displayed answer keys have been matched to official CBSE marking schemes. Explanations are written by Team TutorVertex using NCERT-style methods. Repeated questions are merged; all verified appearances and the original paper details are listed in the sources.

Answer key
Answers to the five questions above.
QuestionCorrect choice
Q1A
Q2A
Q3A
Q4D
Q5D
Understand the reason behind the answer.

Personalised 1-to-1 Maths tutoring with TutorVertex.

Book a free assessment →

How to solve Assertion–Reason questions

In the official 2026–27 sample papers, Q19 and Q20 in Section A are Assertion–Reason questions worth one mark each. Basic format · Standard format.

  1. Check whether the Assertion is true.
  2. Check whether the Reason is true, separately.
  3. If both are true, decide whether the Reason explains the Assertion.
  4. Match your conclusion to the printed answer choices.
Decision table for the standard choices used on this page
A true?R true?R explains A?Choose
YesYesYesA
YesYesNoB
YesNo—C
NoYes—D
TutorVertex · Master Maths. Build Confidence.